py 选择1

print(weekstr[weekid*3: weekid*3+3])

x=0b1010;print(x)

a = "ac"

b = "bd"

c = a + b

print(c)

x = 1 

x *= 3+5**2

print(x)

str1 = "mysqlsqlserverPostgresQL" 

str2 = "sql"

ncount = str1.count(str2,10) 

print(ncount)

print(s[1:10:3])

上述代码的输出结果是（）。