python

b = 33

def fun():

    global b

    print(b)

    b = 99

    print(b)

fun()

print(b)

def fun2():

    a = 10

    b = 20

a = 3

b = 9

fun2()

print(a, b)

def fn(num):

    if num == 1:

        result = 1

    else:

        result = fn(num - 1) * num

    return result

n = int(input("请输入一个正整数:"))

print("%d!=" % n, fn(n))

import random

school_teams = [[], [], []]

student_names = ["李小明", "李明", "李二明", "李白",

                 "李狗蛋", "李赣麻", "李勾八", "李白白"]

for name in student_names:

    team_number = random.randint(0, 2)

    school_teams[team_number].append(name)

for i in school_teams:

    print(i)

可供参考代码段已打乱顺序列举在下：

①  xiaoji = 100 - gongji - muji

②  if (xiaoji % 3 == 0) and (5 * gongji + 3 * muji + xiaoji // 3 == 100):

③  for muji in range(0, 34):

④  print("公鸡：%d只，母鸡：%d只，小鸡：%d只" % (gongji, muji, xiaoji))

⑤  for gongji in range(0, 21):

def fun(x, y):

    x = x + y

    y = x - y

    x = x - y

x = 2

y = 3

fun(x, y)

执行代码后，x和y的值分别为多少。

>>>s[1:4] 含义：________ 运行结果：__________

>>>s.find('A') 含义：_______ 运行结果：_________

# 输出2-2077之间的所有素数

for i in _________:         # 使变量i在2-2077的整数中循环

    fg = 0                      # 设置变量fg，用于标识数字是否为素数

    for j in ______:    # 设置变量j，用于不断地向i变量取余

        if i % j == 0:          # 不断地向i取余

            fg = 1           

            _______        # 得到结果，退出循坏

    if ______:           # 什么场合认定当前数字为素数

        print(____)      # 输出结果